Base | Representation |
---|---|
bin | 111000100000100110… |
… | …1101111011100110001 |
3 | 102121020022110120112122 |
4 | 1301001031233130301 |
5 | 3442012410034203 |
6 | 131425432204025 |
7 | 11524150141046 |
oct | 1610115573461 |
9 | 377208416478 |
10 | 121353205553 |
11 | 475137a2518 |
12 | 1b628b39615 |
13 | b59c660808 |
14 | 5c32d571cd |
15 | 3253ba5538 |
hex | 1c4136f731 |
121353205553 has 4 divisors (see below), whose sum is σ = 124175373168. Its totient is φ = 118531037940.
The previous prime is 121353205543. The next prime is 121353205583. The reversal of 121353205553 is 355502353121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 121353205553 - 24 = 121353205537 is a prime.
It is not an unprimeable number, because it can be changed into a prime (121353205543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1411083743 + ... + 1411083828.
It is an arithmetic number, because the mean of its divisors is an integer number (31043843292).
Almost surely, 2121353205553 is an apocalyptic number.
It is an amenable number.
121353205553 is a deficient number, since it is larger than the sum of its proper divisors (2822167615).
121353205553 is an equidigital number, since it uses as much as digits as its factorization.
121353205553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2822167614.
The product of its (nonzero) digits is 67500, while the sum is 35.
Adding to 121353205553 its reverse (355502353121), we get a palindrome (476855558674).
The spelling of 121353205553 in words is "one hundred twenty-one billion, three hundred fifty-three million, two hundred five thousand, five hundred fifty-three".
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