Base | Representation |
---|---|
bin | 1011000010101001001000… |
… | …1111100110001011110001 |
3 | 1120222120112122101002101221 |
4 | 2300222102033212023301 |
5 | 3042400240432444333 |
6 | 41453015303225041 |
7 | 2362042201040506 |
oct | 260522217461361 |
9 | 46876478332357 |
10 | 12140031140593 |
11 | 39606160a8374 |
12 | 144099ba48181 |
13 | 6a0a52865a65 |
14 | 2dd81b3d54ad |
15 | 160bcb743d2d |
hex | b0a923e62f1 |
12140031140593 has 2 divisors, whose sum is σ = 12140031140594. Its totient is φ = 12140031140592.
The previous prime is 12140031140579. The next prime is 12140031140599. The reversal of 12140031140593 is 39504113004121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12115641447009 + 24389693584 = 3480753^2 + 156172^2 .
It is an emirp because it is prime and its reverse (39504113004121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12140031140593 - 229 = 12139494269681 is a prime.
It is not a weakly prime, because it can be changed into another prime (12140031140599) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070015570296 + 6070015570297.
It is an arithmetic number, because the mean of its divisors is an integer number (6070015570297).
Almost surely, 212140031140593 is an apocalyptic number.
It is an amenable number.
12140031140593 is a deficient number, since it is larger than the sum of its proper divisors (1).
12140031140593 is an equidigital number, since it uses as much as digits as its factorization.
12140031140593 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 34.
The spelling of 12140031140593 in words is "twelve trillion, one hundred forty billion, thirty-one million, one hundred forty thousand, five hundred ninety-three".
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