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1214021411331 = 3563718781179
BaseRepresentation
bin10001101010101001010…
…100001010001000000011
311022001121020110121101020
4101222221110022020003
5124342303440130311
62325414100040523
7153465403506201
oct21525124121003
94261536417336
101214021411331
11428955489a43
12177351393143
138a6354824c1
1442a8a7b6071
15218a5b4cc06
hex11aa950a203

1214021411331 has 8 divisors (see below), whose sum is σ = 1621570342080. Its totient is φ = 807910044072.

The previous prime is 1214021411321. The next prime is 1214021411359. The reversal of 1214021411331 is 1331141204121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1214021411331 - 25 = 1214021411299 is a prime.

It is a super-2 number, since 2×12140214113312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1214021411321) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 359388901 + ... + 359392278.

It is an arithmetic number, because the mean of its divisors is an integer number (202696292760).

Almost surely, 21214021411331 is an apocalyptic number.

1214021411331 is a deficient number, since it is larger than the sum of its proper divisors (407548930749).

1214021411331 is an equidigital number, since it uses as much as digits as its factorization.

1214021411331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 718781745.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 1214021411331 its reverse (1331141204121), we get a palindrome (2545162615452).

The spelling of 1214021411331 in words is "one trillion, two hundred fourteen billion, twenty-one million, four hundred eleven thousand, three hundred thirty-one".

Divisors: 1 3 563 1689 718781179 2156343537 404673803777 1214021411331