Base | Representation |
---|---|
bin | 10110100111010101… |
… | …01010111111101011 |
3 | 1011100010122110102211 |
4 | 23103222222333223 |
5 | 144331111111243 |
6 | 5324430105551 |
7 | 606603521563 |
oct | 132352527753 |
9 | 34303573384 |
10 | 12141113323 |
11 | 5170384159 |
12 | 242a04b2b7 |
13 | 11b6471831 |
14 | 832671da3 |
15 | 4b0d46d9d |
hex | 2d3aaafeb |
12141113323 has 2 divisors, whose sum is σ = 12141113324. Its totient is φ = 12141113322.
The previous prime is 12141113317. The next prime is 12141113351. The reversal of 12141113323 is 32331114121.
It is a weak prime.
It is an emirp because it is prime and its reverse (32331114121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12141113323 - 217 = 12140982251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12141113294 and 12141113303.
It is not a weakly prime, because it can be changed into another prime (12141113123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070556661 + 6070556662.
It is an arithmetic number, because the mean of its divisors is an integer number (6070556662).
Almost surely, 212141113323 is an apocalyptic number.
12141113323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12141113323 is an equidigital number, since it uses as much as digits as its factorization.
12141113323 is an evil number, because the sum of its binary digits is even.
The product of its digits is 432, while the sum is 22.
Adding to 12141113323 its reverse (32331114121), we get a palindrome (44472227444).
The spelling of 12141113323 in words is "twelve billion, one hundred forty-one million, one hundred thirteen thousand, three hundred twenty-three".
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