12141123400033 has 2 divisors, whose sum is σ = 12141123400034. Its totient is φ = 12141123400032.

The previous prime is 12141123400019. The next prime is 12141123400039. The reversal of 12141123400033 is 33000432114121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11449784365009 + 691339035024 = 3383753^2 + 831468^2 .

It is a cyclic number.

It is not a de Polignac number, because 12141123400033 - 2⁹ = 12141123399521 is a prime.

It is a super-3 number, since 3×12141123400033³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12141123399980 and 12141123400007.

It is not a weakly prime, because it can be changed into another prime (12141123400039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070561700016 + 6070561700017.

It is an arithmetic number, because the mean of its divisors is an integer number (6070561700017).

Almost surely, 2^{12141123400033} is an apocalyptic number.

It is an amenable number.

12141123400033 is a deficient number, since it is larger than the sum of its proper divisors (1).

12141123400033 is an equidigital number, since it uses as much as digits as its factorization.

12141123400033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 12141123400033 its reverse (33000432114121), we get a palindrome (45141555514154).

The spelling of 12141123400033 in words is "twelve trillion, one hundred forty-one billion, one hundred twenty-three million, four hundred thousand, thirty-three".