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121411535081 is a prime number
BaseRepresentation
bin111000100010010110…
…0010000000011101001
3102121101101020000121112
41301010230100003221
53442122323110311
6131435314320105
711525456010014
oct1610454200351
9377341200545
10121411535081
1147543712341
121b644589035
13b5ab774325
145c3a9bc37b
153258d7828b
hex1c44b100e9

121411535081 has 2 divisors, whose sum is σ = 121411535082. Its totient is φ = 121411535080.

The previous prime is 121411534997. The next prime is 121411535099. The reversal of 121411535081 is 180535114121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93125677225 + 28285857856 = 305165^2 + 168184^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121411535081 is a prime.

It is a super-2 number, since 2×1214115350812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (121411535881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60705767540 + 60705767541.

It is an arithmetic number, because the mean of its divisors is an integer number (60705767541).

Almost surely, 2121411535081 is an apocalyptic number.

It is an amenable number.

121411535081 is a deficient number, since it is larger than the sum of its proper divisors (1).

121411535081 is an equidigital number, since it uses as much as digits as its factorization.

121411535081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 32.

The spelling of 121411535081 in words is "one hundred twenty-one billion, four hundred eleven million, five hundred thirty-five thousand, eighty-one".