12141221214433 has 4 divisors (see below), whose sum is σ = 12423575196208. Its totient is φ = 11858867232660.

The previous prime is 12141221214427. The next prime is 12141221214443. The reversal of 12141221214433 is 33441212214121.

12141221214433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12141221214433 - 2²⁵ = 12141187660001 is a prime.

It is a super-2 number, since 2×12141221214433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12141221214395 and 12141221214404.

It is not an unprimeable number, because it can be changed into a prime (12141221214403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141176990823 + ... + 141176990908.

It is an arithmetic number, because the mean of its divisors is an integer number (3105893799052).

Almost surely, 2^{12141221214433} is an apocalyptic number.

It is an amenable number.

12141221214433 is a deficient number, since it is larger than the sum of its proper divisors (282353981775).

12141221214433 is an equidigital number, since it uses as much as digits as its factorization.

12141221214433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 282353981774.

The product of its digits is 9216, while the sum is 31.

Adding to 12141221214433 its reverse (33441212214121), we get a palindrome (45582433428554).

The spelling of 12141221214433 in words is "twelve trillion, one hundred forty-one billion, two hundred twenty-one million, two hundred fourteen thousand, four hundred thirty-three".