Base | Representation |
---|---|
bin | 1011000010101101110111… |
… | …1000000001111100001011 |
3 | 1120222200211002000102010221 |
4 | 2300223131320001330023 |
5 | 3042410340301444433 |
6 | 41453345232050511 |
7 | 2362115506322245 |
oct | 260533570017413 |
9 | 46880732012127 |
10 | 12141300031243 |
11 | 3961107387729 |
12 | 1441094993a37 |
13 | 6a0bc56cab26 |
14 | 2dd8dbb39095 |
15 | 160c52d3b72d |
hex | b0adde01f0b |
12141300031243 has 2 divisors, whose sum is σ = 12141300031244. Its totient is φ = 12141300031242.
The previous prime is 12141300031151. The next prime is 12141300031247. The reversal of 12141300031243 is 34213000314121.
12141300031243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12141300031243 is a prime.
It is a super-2 number, since 2×121413000312432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12141300031247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070650015621 + 6070650015622.
It is an arithmetic number, because the mean of its divisors is an integer number (6070650015622).
Almost surely, 212141300031243 is an apocalyptic number.
12141300031243 is a deficient number, since it is larger than the sum of its proper divisors (1).
12141300031243 is an equidigital number, since it uses as much as digits as its factorization.
12141300031243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 12141300031243 its reverse (34213000314121), we get a palindrome (46354300345364).
The spelling of 12141300031243 in words is "twelve trillion, one hundred forty-one billion, three hundred million, thirty-one thousand, two hundred forty-three".
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