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12141424433 = 18167079693
BaseRepresentation
bin10110100111010111…
…10110111100110001
31011100011020021012102
423103223312330301
5144331201040213
65324440510145
7606606255605
oct132353667461
934304207172
1012141424433
115170576976
12242a17b355
1311b6550318
14832713505
154b0da9158
hex2d3af6f31

12141424433 has 4 divisors (see below), whose sum is σ = 12208504308. Its totient is φ = 12074344560.

The previous prime is 12141424357. The next prime is 12141424489. The reversal of 12141424433 is 33442414121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 672727969 + 11468696464 = 25937^2 + 107092^2 .

It is a cyclic number.

It is not a de Polignac number, because 12141424433 - 216 = 12141358897 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12141424396 and 12141424405.

It is not an unprimeable number, because it can be changed into a prime (12141424033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33539666 + ... + 33540027.

It is an arithmetic number, because the mean of its divisors is an integer number (3052126077).

Almost surely, 212141424433 is an apocalyptic number.

It is an amenable number.

12141424433 is a deficient number, since it is larger than the sum of its proper divisors (67079875).

12141424433 is an equidigital number, since it uses as much as digits as its factorization.

12141424433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67079874.

The product of its digits is 9216, while the sum is 29.

Adding to 12141424433 its reverse (33442414121), we get a palindrome (45583838554).

The spelling of 12141424433 in words is "twelve billion, one hundred forty-one million, four hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 181 67079693 12141424433