1214201531131 has 4 divisors (see below), whose sum is σ = 1243816202664. Its totient is φ = 1184586859600.

The previous prime is 1214201531093. The next prime is 1214201531227. The reversal of 1214201531131 is 1311351024121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1214201531131 - 2¹¹ = 1214201529083 is a prime.

It is a super-2 number, since 2×1214201531131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1214201531096 and 1214201531105.

It is not an unprimeable number, because it can be changed into a prime (1214201531731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14807335705 + ... + 14807335786.

It is an arithmetic number, because the mean of its divisors is an integer number (310954050666).

Almost surely, 2^{1214201531131} is an apocalyptic number.

1214201531131 is a deficient number, since it is larger than the sum of its proper divisors (29614671533).

1214201531131 is an equidigital number, since it uses as much as digits as its factorization.

1214201531131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29614671532.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 1214201531131 its reverse (1311351024121), we get a palindrome (2525552555252).

The spelling of 1214201531131 in words is "one trillion, two hundred fourteen billion, two hundred one million, five hundred thirty-one thousand, one hundred thirty-one".