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121420254451 = 399833036797
BaseRepresentation
bin111000100010100110…
…1100000110011110011
3102121101222122000100011
41301011031200303303
53442132041120301
6131440225235351
711525623063636
oct1610515406363
9377358560304
10121420254451
1147548628331
121b647492b57
13b5b0508012
145c3bc0bc1d
1532599eba51
hex1c45360cf3

121420254451 has 4 divisors (see below), whose sum is σ = 121423331232. Its totient is φ = 121417177672.

The previous prime is 121420254427. The next prime is 121420254457. The reversal of 121420254451 is 154452024121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121420254451 - 223 = 121411865843 is a prime.

It is a super-2 number, since 2×1214202544512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121420254457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1478416 + ... + 1558381.

It is an arithmetic number, because the mean of its divisors is an integer number (30355832808).

Almost surely, 2121420254451 is an apocalyptic number.

121420254451 is a deficient number, since it is larger than the sum of its proper divisors (3076781).

121420254451 is an equidigital number, since it uses as much as digits as its factorization.

121420254451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3076780.

The product of its (nonzero) digits is 12800, while the sum is 31.

Adding to 121420254451 its reverse (154452024121), we get a palindrome (275872278572).

The spelling of 121420254451 in words is "one hundred twenty-one billion, four hundred twenty million, two hundred fifty-four thousand, four hundred fifty-one".

Divisors: 1 39983 3036797 121420254451