12142104433 has 2 divisors, whose sum is σ = 12142104434. Its totient is φ = 12142104432.

The previous prime is 12142104389. The next prime is 12142104493. The reversal of 12142104433 is 33440124121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9939491809 + 2202612624 = 99697^2 + 46932^2 .

It is a cyclic number.

It is not a de Polignac number, because 12142104433 - 2²¹ = 12140007281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12142104398 and 12142104407.

It is not a weakly prime, because it can be changed into another prime (12142104493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071052216 + 6071052217.

It is an arithmetic number, because the mean of its divisors is an integer number (6071052217).

Almost surely, 2^12142104433 is an apocalyptic number.

It is an amenable number.

12142104433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12142104433 is an equidigital number, since it uses as much as digits as its factorization.

12142104433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12142104433 its reverse (33440124121), we get a palindrome (45582228554).

The spelling of 12142104433 in words is "twelve billion, one hundred forty-two million, one hundred four thousand, four hundred thirty-three".