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1214223010153 is a prime number
BaseRepresentation
bin10001101010110101010…
…101001100100101101001
311022002010021210212222021
4101222311111030211221
5124343212042311103
62325450101024441
7153503402202646
oct21526525144551
94262107725867
101214223010153
11428a4926413a
121773a89b5121
138a66817944a
1442aa9492dcd
15218b86c0bbd
hex11ab554c969

1214223010153 has 2 divisors, whose sum is σ = 1214223010154. Its totient is φ = 1214223010152.

The previous prime is 1214223010079. The next prime is 1214223010213. The reversal of 1214223010153 is 3510103224121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 632401886169 + 581821123984 = 795237^2 + 762772^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1214223010153 is a prime.

It is not a weakly prime, because it can be changed into another prime (1214223014153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607111505076 + 607111505077.

It is an arithmetic number, because the mean of its divisors is an integer number (607111505077).

Almost surely, 21214223010153 is an apocalyptic number.

It is an amenable number.

1214223010153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214223010153 is an equidigital number, since it uses as much as digits as its factorization.

1214223010153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1214223010153 its reverse (3510103224121), we get a palindrome (4724326234274).

The spelling of 1214223010153 in words is "one trillion, two hundred fourteen billion, two hundred twenty-three million, ten thousand, one hundred fifty-three".