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12142433 is a prime number
BaseRepresentation
bin101110010100…
…011101100001
3211211220021202
4232110131201
511102024213
61112130545
7205131452
oct56243541
924756252
1012142433
116943876
124096a55
132691a94
141881129
1510ecb58
hexb94761

12142433 has 2 divisors, whose sum is σ = 12142434. Its totient is φ = 12142432.

The previous prime is 12142423. The next prime is 12142439. The reversal of 12142433 is 33424121.

12142433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6492304 + 5650129 = 2548^2 + 2377^2 .

It is an emirp because it is prime and its reverse (33424121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12142433 - 28 = 12142177 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12142439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071216 + 6071217.

It is an arithmetic number, because the mean of its divisors is an integer number (6071217).

Almost surely, 212142433 is an apocalyptic number.

It is an amenable number.

12142433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12142433 is an equidigital number, since it uses as much as digits as its factorization.

12142433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 576, while the sum is 20.

The square root of 12142433 is about 3484.5994030878. The cubic root of 12142433 is about 229.8450941815.

Adding to 12142433 its reverse (33424121), we get a palindrome (45566554).

The spelling of 12142433 in words is "twelve million, one hundred forty-two thousand, four hundred thirty-three".