Base | Representation |
---|---|
bin | 1011000010110100101001… |
… | …1110110011010001101000 |
3 | 1120222212112001121211101200 |
4 | 2300231022132303101220 |
5 | 3042423103231242440 |
6 | 41454250122044200 |
7 | 2362211613044445 |
oct | 260551236632150 |
9 | 46885461554350 |
10 | 12143122134120 |
11 | 396196196857a |
12 | 1441503049660 |
13 | 6a1126059503 |
14 | 2dda31b269cc |
15 | 160d0ccadc30 |
hex | b0b4a7b3468 |
12143122134120 has 192 divisors, whose sum is σ = 39554745506640. Its totient is φ = 3230820864000.
The previous prime is 12143122134083. The next prime is 12143122134151. The reversal of 12143122134120 is 2143122134121.
12143122134120 is a `hidden beast` number, since 1 + 2 + 1 + 4 + 31 + 2 + 213 + 412 + 0 = 666.
It can be written as a sum of positive squares in 8 ways, for example, as 6741095635044 + 5402026499076 = 2596362^2 + 2324226^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 376666642 + ... + 376698878.
Almost surely, 212143122134120 is an apocalyptic number.
12143122134120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12143122134120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19777372753320).
12143122134120 is an abundant number, since it is smaller than the sum of its proper divisors (27411623372520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12143122134120 is a wasteful number, since it uses less digits than its factorization.
12143122134120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34596 (or 34589 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 12143122134120 its reverse (2143122134121), we get a palindrome (14286244268241).
Subtracting from 12143122134120 its reverse (2143122134121), we obtain a palindrome (9999999999999).
The spelling of 12143122134120 in words is "twelve trillion, one hundred forty-three billion, one hundred twenty-two million, one hundred thirty-four thousand, one hundred twenty".
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