Base | Representation |
---|---|
bin | 111000100010111110… |
… | …0010110110000010011 |
3 | 102121102211201212202120 |
4 | 1301011330112300103 |
5 | 3442143212042120 |
6 | 131441344345323 |
7 | 11526132336321 |
oct | 1610574266023 |
9 | 377384655676 |
10 | 121432534035 |
11 | 4755455514a |
12 | 1b64b615243 |
13 | b5b2c17347 |
14 | 5c3d6c6d11 |
15 | 325ab25140 |
hex | 1c45f16c13 |
121432534035 has 16 divisors (see below), whose sum is σ = 196011455904. Its totient is φ = 64190884352.
The previous prime is 121432534031. The next prime is 121432534081. The reversal of 121432534035 is 530435234121.
It is a cyclic number.
It is not a de Polignac number, because 121432534035 - 22 = 121432534031 is a prime.
It is a super-2 number, since 2×1214325340352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121432533987 and 121432534005.
It is not an unprimeable number, because it can be changed into a prime (121432534031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35819112 + ... + 35822501.
It is an arithmetic number, because the mean of its divisors is an integer number (12250715994).
Almost surely, 2121432534035 is an apocalyptic number.
121432534035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
121432534035 is a deficient number, since it is larger than the sum of its proper divisors (74578921869).
121432534035 is a wasteful number, since it uses less digits than its factorization.
121432534035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71641734.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 121432534035 its reverse (530435234121), we get a palindrome (651867768156).
The spelling of 121432534035 in words is "one hundred twenty-one billion, four hundred thirty-two million, five hundred thirty-four thousand, thirty-five".
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