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121441201747193 is a prime number
BaseRepresentation
bin11011100111001100111011…
…101100001111010011111001
3120220222122222011010110011002
4123213030323230033103321
5111404143040121402233
61110141152400014345
734402560122001146
oct3347147354172371
9526878864113132
10121441201747193
1135770a19469a39
12117541509013b5
13529bb1906c8c3
1421dbadd6ad3cd
15e08e6ea306e8
hex6e733bb0f4f9

121441201747193 has 2 divisors, whose sum is σ = 121441201747194. Its totient is φ = 121441201747192.

The previous prime is 121441201747183. The next prime is 121441201747223. The reversal of 121441201747193 is 391747102144121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 67960106539264 + 53481095207929 = 8243792^2 + 7313077^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121441201747193 is a prime.

It is not a weakly prime, because it can be changed into another prime (121441201747153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60720600873596 + 60720600873597.

It is an arithmetic number, because the mean of its divisors is an integer number (60720600873597).

Almost surely, 2121441201747193 is an apocalyptic number.

It is an amenable number.

121441201747193 is a deficient number, since it is larger than the sum of its proper divisors (1).

121441201747193 is an equidigital number, since it uses as much as digits as its factorization.

121441201747193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 338688, while the sum is 47.

The spelling of 121441201747193 in words is "one hundred twenty-one trillion, four hundred forty-one billion, two hundred one million, seven hundred forty-seven thousand, one hundred ninety-three".