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1214413022113 = 1499218100353
BaseRepresentation
bin10001101011000000101…
…010000010001110100001
311022002121112100111101021
4101223000222002032201
5124344104213201423
62325521005405441
7153511200240454
oct21530052021641
94262545314337
101214413022113
11429036544a15
12177440569881
138a698647465
1442ac67d549b
15218ca20595d
hex11ac0a823a1

1214413022113 has 4 divisors (see below), whose sum is σ = 1214421272388. Its totient is φ = 1214404771840.

The previous prime is 1214413021999. The next prime is 1214413022149. The reversal of 1214413022113 is 3112203144121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 199824198289 + 1014588823824 = 447017^2 + 1007268^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1214413022113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1214413022213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3900256 + ... + 4200097.

It is an arithmetic number, because the mean of its divisors is an integer number (303605318097).

Almost surely, 21214413022113 is an apocalyptic number.

It is an amenable number.

1214413022113 is a deficient number, since it is larger than the sum of its proper divisors (8250275).

1214413022113 is an equidigital number, since it uses as much as digits as its factorization.

1214413022113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8250274.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1214413022113 its reverse (3112203144121), we get a palindrome (4326616166234).

The spelling of 1214413022113 in words is "one trillion, two hundred fourteen billion, four hundred thirteen million, twenty-two thousand, one hundred thirteen".

Divisors: 1 149921 8100353 1214413022113