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121442113302131 is a prime number
BaseRepresentation
bin11011100111001101110010…
…000001100010111001110011
3120220222202022200101020110002
4123213031302001202321303
5111404201422001132011
61110141423041500215
734402621531043546
oct3347156201427163
9526882280336402
10121442113302131
1135771346a73726
121175436604166b
13529bc32b8081b
1421dbb8879685d
15e08ec4a90c3b
hex6e7372062e73

121442113302131 has 2 divisors, whose sum is σ = 121442113302132. Its totient is φ = 121442113302130.

The previous prime is 121442113302127. The next prime is 121442113302163. The reversal of 121442113302131 is 131203311244121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 121442113302131 - 22 = 121442113302127 is a prime.

It is a super-2 number, since 2×1214421133021312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121442113302094 and 121442113302103.

It is not a weakly prime, because it can be changed into another prime (121442113302121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60721056651065 + 60721056651066.

It is an arithmetic number, because the mean of its divisors is an integer number (60721056651066).

Almost surely, 2121442113302131 is an apocalyptic number.

121442113302131 is a deficient number, since it is larger than the sum of its proper divisors (1).

121442113302131 is an equidigital number, since it uses as much as digits as its factorization.

121442113302131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 121442113302131 its reverse (131203311244121), we get a palindrome (252645424546252).

The spelling of 121442113302131 in words is "one hundred twenty-one trillion, four hundred forty-two billion, one hundred thirteen million, three hundred two thousand, one hundred thirty-one".