1214443324331 has 4 divisors (see below), whose sum is σ = 1214446473000. Its totient is φ = 1214440175664.

The previous prime is 1214443324291. The next prime is 1214443324427. The reversal of 1214443324331 is 1334233444121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1214443324331 is a prime.

It is a super-2 number, since 2×1214443324331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1214443324291 and 1214443324300.

It is not an unprimeable number, because it can be changed into a prime (1214443324231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 899306 + ... + 1799343.

It is an arithmetic number, because the mean of its divisors is an integer number (303611618250).

Almost surely, 2^{1214443324331} is an apocalyptic number.

1214443324331 is a deficient number, since it is larger than the sum of its proper divisors (3148669).

1214443324331 is an equidigital number, since it uses as much as digits as its factorization.

1214443324331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3148668.

The product of its digits is 82944, while the sum is 35.

Adding to 1214443324331 its reverse (1334233444121), we get a palindrome (2548676768452).

The spelling of 1214443324331 in words is "one trillion, two hundred fourteen billion, four hundred forty-three million, three hundred twenty-four thousand, three hundred thirty-one".