Base | Representation |
---|---|
bin | 10001101011000110101… |
… | …000101110011110001011 |
3 | 11022002212112010021212111 |
4 | 101223012220232132023 |
5 | 124344310403423342 |
6 | 2325534551523151 |
7 | 153513526035334 |
oct | 21530650563613 |
9 | 4262775107774 |
10 | 1214513342347 |
11 | 429088134aa8 |
12 | 17746a0894b7 |
13 | 8a6b3370946 |
14 | 42ad5c6b28b |
15 | 218d3e20217 |
hex | 11ac6a2e78b |
1214513342347 has 2 divisors, whose sum is σ = 1214513342348. Its totient is φ = 1214513342346.
The previous prime is 1214513342327. The next prime is 1214513342351. The reversal of 1214513342347 is 7432433154121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1214513342347 is a prime.
It is not a weakly prime, because it can be changed into another prime (1214513342327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607256671173 + 607256671174.
It is an arithmetic number, because the mean of its divisors is an integer number (607256671174).
Almost surely, 21214513342347 is an apocalyptic number.
1214513342347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1214513342347 is an equidigital number, since it uses as much as digits as its factorization.
1214513342347 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 241920, while the sum is 40.
Adding to 1214513342347 its reverse (7432433154121), we get a palindrome (8646946496468).
The spelling of 1214513342347 in words is "one trillion, two hundred fourteen billion, five hundred thirteen million, three hundred forty-two thousand, three hundred forty-seven".
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