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1214553114017 is a prime number
BaseRepresentation
bin10001101011001001000…
…000011100010110100001
311022002222021221220100022
4101223021000130112201
5124344401044122032
62325542532203225
7153514521062615
oct21531100342641
94262867856308
101214553114017
114290a862a051
1217747b469515
138a6bb687589
1442adb261345
15218d7679512
hex11ac901c5a1

1214553114017 has 2 divisors, whose sum is σ = 1214553114018. Its totient is φ = 1214553114016.

The previous prime is 1214553114011. The next prime is 1214553114107. The reversal of 1214553114017 is 7104113554121.

Together with next prime (1214553114107) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1083689328016 + 130863786001 = 1041004^2 + 361751^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1214553114017 is a prime.

It is not a weakly prime, because it can be changed into another prime (1214553114011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607276557008 + 607276557009.

It is an arithmetic number, because the mean of its divisors is an integer number (607276557009).

Almost surely, 21214553114017 is an apocalyptic number.

It is an amenable number.

1214553114017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214553114017 is an equidigital number, since it uses as much as digits as its factorization.

1214553114017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16800, while the sum is 35.

Adding to 1214553114017 its reverse (7104113554121), we get a palindrome (8318666668138).

The spelling of 1214553114017 in words is "one trillion, two hundred fourteen billion, five hundred fifty-three million, one hundred fourteen thousand, seventeen".