Base | Representation |
---|---|
bin | 1011000010111110000100… |
… | …1010101111001111110001 |
3 | 1121000010001020200121221122 |
4 | 2300233201022233033301 |
5 | 3042443242424444403 |
6 | 41455345032032025 |
7 | 2362331351410166 |
oct | 260574112571761 |
9 | 47003036617848 |
10 | 12145650234353 |
11 | 3962a39a14709 |
12 | 1441aa9832615 |
13 | 6a1439a46ccc |
14 | 2ddbd17b006d |
15 | 160e09bda838 |
hex | b0be12af3f1 |
12145650234353 has 2 divisors, whose sum is σ = 12145650234354. Its totient is φ = 12145650234352.
The previous prime is 12145650234293. The next prime is 12145650234359. The reversal of 12145650234353 is 35343205654121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9996397477264 + 2149252757089 = 3161708^2 + 1466033^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12145650234353 is a prime.
It is not a weakly prime, because it can be changed into another prime (12145650234359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6072825117176 + 6072825117177.
It is an arithmetic number, because the mean of its divisors is an integer number (6072825117177).
Almost surely, 212145650234353 is an apocalyptic number.
It is an amenable number.
12145650234353 is a deficient number, since it is larger than the sum of its proper divisors (1).
12145650234353 is an equidigital number, since it uses as much as digits as its factorization.
12145650234353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296000, while the sum is 44.
Adding to 12145650234353 its reverse (35343205654121), we get a palindrome (47488855888474).
The spelling of 12145650234353 in words is "twelve trillion, one hundred forty-five billion, six hundred fifty million, two hundred thirty-four thousand, three hundred fifty-three".
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