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12146132403233 is a prime number
BaseRepresentation
bin1011000010111111110111…
…1010000100010000100001
31121000011021211222100022022
42300233331322010100201
53043000234343400413
641455504534351225
72362346324650313
oct260577572042041
947004254870268
1012146132403233
113963167102294
1214420031bb515
136a14b58c7c3a
142ddc398437b3
15160e371d0608
hexb0bfde84421

12146132403233 has 2 divisors, whose sum is σ = 12146132403234. Its totient is φ = 12146132403232.

The previous prime is 12146132403191. The next prime is 12146132403239. The reversal of 12146132403233 is 33230423164121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10458128613409 + 1688003789824 = 3233903^2 + 1299232^2 .

It is a cyclic number.

It is not a de Polignac number, because 12146132403233 - 240 = 11046620775457 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12146132403193 and 12146132403202.

It is not a weakly prime, because it can be changed into another prime (12146132403239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6073066201616 + 6073066201617.

It is an arithmetic number, because the mean of its divisors is an integer number (6073066201617).

Almost surely, 212146132403233 is an apocalyptic number.

It is an amenable number.

12146132403233 is a deficient number, since it is larger than the sum of its proper divisors (1).

12146132403233 is an equidigital number, since it uses as much as digits as its factorization.

12146132403233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 12146132403233 its reverse (33230423164121), we get a palindrome (45376555567354).

The spelling of 12146132403233 in words is "twelve trillion, one hundred forty-six billion, one hundred thirty-two million, four hundred three thousand, two hundred thirty-three".