Base | Representation |
---|---|
bin | 10001101011010100011… |
… | …110001111000001111011 |
3 | 11022010110200220202110112 |
4 | 101223110132033001323 |
5 | 124400244320120042 |
6 | 2330014003134535 |
7 | 153522345104453 |
oct | 21532436170173 |
9 | 4263420822415 |
10 | 1214745473147 |
11 | 429197173338 |
12 | 17751397444b |
13 | 8a71c497a4b |
14 | 42b18a14d63 |
15 | 218e94c4982 |
hex | 11ad478f07b |
1214745473147 has 2 divisors, whose sum is σ = 1214745473148. Its totient is φ = 1214745473146.
The previous prime is 1214745473143. The next prime is 1214745473233. The reversal of 1214745473147 is 7413745474121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1214745473147 - 22 = 1214745473143 is a prime.
It is a super-2 number, since 2×12147454731472 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1214745473095 and 1214745473104.
It is not a weakly prime, because it can be changed into another prime (1214745473143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607372736573 + 607372736574.
It is an arithmetic number, because the mean of its divisors is an integer number (607372736574).
Almost surely, 21214745473147 is an apocalyptic number.
1214745473147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1214745473147 is an equidigital number, since it uses as much as digits as its factorization.
1214745473147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2634240, while the sum is 50.
The spelling of 1214745473147 in words is "one trillion, two hundred fourteen billion, seven hundred forty-five million, four hundred seventy-three thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.061 sec. • engine limits •