121488000113 has 2 divisors, whose sum is σ = 121488000114. Its totient is φ = 121488000112.

The previous prime is 121488000089. The next prime is 121488000119. The reversal of 121488000113 is 311000884121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86841017344 + 34646982769 = 294688^2 + 186137^2 .

It is an emirp because it is prime and its reverse (311000884121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121488000113 - 2²⁴ = 121471222897 is a prime.

It is not a weakly prime, because it can be changed into another prime (121488000119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60744000056 + 60744000057.

It is an arithmetic number, because the mean of its divisors is an integer number (60744000057).

Almost surely, 2^121488000113 is an apocalyptic number.

It is an amenable number.

121488000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121488000113 is an equidigital number, since it uses as much as digits as its factorization.

121488000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 29.

Adding to 121488000113 its reverse (311000884121), we get a palindrome (432488884234).

The spelling of 121488000113 in words is "one hundred twenty-one billion, four hundred eighty-eight million, one hundred thirteen", and thus it is an aban number.