12151101024433 has 4 divisors (see below), whose sum is σ = 13886972599360. Its totient is φ = 10415229449508.

The previous prime is 12151101024407. The next prime is 12151101024509. The reversal of 12151101024433 is 33442010115121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12151101024433 is a prime.

It is a super-2 number, since 2×12151101024433² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (12151101025433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 867935787453 + ... + 867935787466.

It is an arithmetic number, because the mean of its divisors is an integer number (3471743149840).

Almost surely, 2^{12151101024433} is an apocalyptic number.

It is an amenable number.

12151101024433 is a deficient number, since it is larger than the sum of its proper divisors (1735871574927).

12151101024433 is an equidigital number, since it uses as much as digits as its factorization.

12151101024433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1735871574926.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 12151101024433 its reverse (33442010115121), we get a palindrome (45593111139554).

The spelling of 12151101024433 in words is "twelve trillion, one hundred fifty-one billion, one hundred one million, twenty-four thousand, four hundred thirty-three".