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12153113 = 717731399
BaseRepresentation
bin101110010111…
…000100011001
3211212102221022
4232113010121
511102344423
61112252225
7205204550
oct56270431
924772838
1012153113
1169508a5
1240a1075
1326968bb
141884d97
151100dc8
hexb97119

12153113 has 16 divisors (see below), whose sum is σ = 14918400. Its totient is φ = 9662976.

The previous prime is 12153101. The next prime is 12153121. The reversal of 12153113 is 31135121.

12153113 is digitally balanced in base 2 and base 8, because in such bases it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 12153113 - 218 = 11890969 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17).

12153113 is strictly pandigital in base 8.

It is a junction number, because it is equal to n+sod(n) for n = 12153091 and 12153100.

It is not an unprimeable number, because it can be changed into a prime (12153143) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7988 + ... + 9386.

It is an arithmetic number, because the mean of its divisors is an integer number (932400).

Almost surely, 212153113 is an apocalyptic number.

It is an amenable number.

12153113 is a deficient number, since it is larger than the sum of its proper divisors (2765287).

12153113 is a wasteful number, since it uses less digits than its factorization.

12153113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1496.

The product of its digits is 90, while the sum is 17.

The square root of 12153113 is about 3486.1315236233. The cubic root of 12153113 is about 229.9124619613.

Adding to 12153113 its reverse (31135121), we get a palindrome (43288234).

The spelling of 12153113 in words is "twelve million, one hundred fifty-three thousand, one hundred thirteen".

Divisors: 1 7 17 73 119 511 1241 1399 8687 9793 23783 102127 166481 714889 1736159 12153113