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12153422535403 = 73166485240211
BaseRepresentation
bin1011000011011011000001…
…1011101101101011101011
31121000212002220122102121111
42300312300123231223223
53043110202132113103
641503112155251151
72363025066030052
oct260666033555353
947025086572544
1012153422535403
113966268200506
1214434b8749ab7
136a20a8055306
1430032bb25399
1516121220986d
hexb0db06edaeb

12153422535403 has 4 divisors (see below), whose sum is σ = 12319907775688. Its totient is φ = 11986937295120.

The previous prime is 12153422535349. The next prime is 12153422535437. The reversal of 12153422535403 is 30453522435121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12153422535403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12153422532403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83242620033 + ... + 83242620178.

It is an arithmetic number, because the mean of its divisors is an integer number (3079976943922).

Almost surely, 212153422535403 is an apocalyptic number.

12153422535403 is a deficient number, since it is larger than the sum of its proper divisors (166485240285).

12153422535403 is an equidigital number, since it uses as much as digits as its factorization.

12153422535403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 166485240284.

The product of its (nonzero) digits is 432000, while the sum is 40.

The spelling of 12153422535403 in words is "twelve trillion, one hundred fifty-three billion, four hundred twenty-two million, five hundred thirty-five thousand, four hundred three".

Divisors: 1 73 166485240211 12153422535403