1215440403403 has 4 divisors (see below), whose sum is σ = 1216858654440. Its totient is φ = 1214022152368.

The previous prime is 1215440403371. The next prime is 1215440403427. The reversal of 1215440403403 is 3043040445121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1215440403403 - 2⁵ = 1215440403371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1215440403803) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 709124233 + ... + 709125946.

It is an arithmetic number, because the mean of its divisors is an integer number (304214663610).

Almost surely, 2^{1215440403403} is an apocalyptic number.

1215440403403 is a deficient number, since it is larger than the sum of its proper divisors (1418251037).

1215440403403 is an equidigital number, since it uses as much as digits as its factorization.

1215440403403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1418251036.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 1215440403403 its reverse (3043040445121), we get a palindrome (4258480848524).

The spelling of 1215440403403 in words is "one trillion, two hundred fifteen billion, four hundred forty million, four hundred three thousand, four hundred three".