1215552101433 has 16 divisors (see below), whose sum is σ = 1634508308160. Its totient is φ = 803497068864.

The previous prime is 1215552101399. The next prime is 1215552101437. The reversal of 1215552101433 is 3341012555121.

It is not a de Polignac number, because 1215552101433 - 2²² = 1215547907129 is a prime.

It is a super-2 number, since 2×1215552101433² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1215552101394 and 1215552101403.

It is not an unprimeable number, because it can be changed into a prime (1215552101437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1563166 + ... + 2207847.

It is an arithmetic number, because the mean of its divisors is an integer number (102156769260).

Almost surely, 2^{1215552101433} is an apocalyptic number.

It is an amenable number.

1215552101433 is a deficient number, since it is larger than the sum of its proper divisors (418956206727).

1215552101433 is a wasteful number, since it uses less digits than its factorization.

1215552101433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3771928.

The product of its (nonzero) digits is 18000, while the sum is 33.

Adding to 1215552101433 its reverse (3341012555121), we get a palindrome (4556564656554).

The spelling of 1215552101433 in words is "one trillion, two hundred fifteen billion, five hundred fifty-two million, one hundred one thousand, four hundred thirty-three".