Base | Representation |
---|---|
bin | 10001101100000100101… |
… | …011011001101101011011 |
3 | 11022012120001201220211221 |
4 | 101230010223121231123 |
5 | 124403423340344011 |
6 | 2330230133432511 |
7 | 153551365325452 |
oct | 21540453315533 |
9 | 4265501656757 |
10 | 1215554231131 |
11 | 429571746169 |
12 | 1776ba79b737 |
13 | 8a81abc6076 |
14 | 42b941bdb99 |
15 | 219454cb971 |
hex | 11b04ad9b5b |
1215554231131 has 2 divisors, whose sum is σ = 1215554231132. Its totient is φ = 1215554231130.
The previous prime is 1215554231051. The next prime is 1215554231167. The reversal of 1215554231131 is 1311324555121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1215554231131 - 227 = 1215420013403 is a prime.
It is a super-2 number, since 2×12155542311312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1215554231431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607777115565 + 607777115566.
It is an arithmetic number, because the mean of its divisors is an integer number (607777115566).
Almost surely, 21215554231131 is an apocalyptic number.
1215554231131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1215554231131 is an equidigital number, since it uses as much as digits as its factorization.
1215554231131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18000, while the sum is 34.
Adding to 1215554231131 its reverse (1311324555121), we get a palindrome (2526878786252).
The spelling of 1215554231131 in words is "one trillion, two hundred fifteen billion, five hundred fifty-four million, two hundred thirty-one thousand, one hundred thirty-one".
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