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121557350561 is a prime number
BaseRepresentation
bin111000100110101100…
…0011111100010100001
3102121202112121012211212
41301031120133202201
53442422140204221
6131502003515505
711532206301023
oct1611530374241
9377675535755
10121557350561
1147608a566a9
121b685388b95
13b602a3968a
145c520d8013
153266a7cb5b
hex1c4d61f8a1

121557350561 has 2 divisors, whose sum is σ = 121557350562. Its totient is φ = 121557350560.

The previous prime is 121557350557. The next prime is 121557350587. The reversal of 121557350561 is 165053755121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121535904400 + 21446161 = 348620^2 + 4631^2 .

It is an emirp because it is prime and its reverse (165053755121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121557350561 - 22 = 121557350557 is a prime.

It is a super-3 number, since 3×1215573505613 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (121557358561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60778675280 + 60778675281.

It is an arithmetic number, because the mean of its divisors is an integer number (60778675281).

Almost surely, 2121557350561 is an apocalyptic number.

It is an amenable number.

121557350561 is a deficient number, since it is larger than the sum of its proper divisors (1).

121557350561 is an equidigital number, since it uses as much as digits as its factorization.

121557350561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 157500, while the sum is 41.

The spelling of 121557350561 in words is "one hundred twenty-one billion, five hundred fifty-seven million, three hundred fifty thousand, five hundred sixty-one".