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121761304673 is a prime number
BaseRepresentation
bin111000101100110001…
…0100001000001100001
3102122021202101011021212
41301121202201001201
53443331343222143
6131534131155505
711540234004311
oct1613142410141
9378252334255
10121761304673
114770309a418
121b721745b95
13b636079698
145c71229441
153279918918
hex1c598a1061

121761304673 has 2 divisors, whose sum is σ = 121761304674. Its totient is φ = 121761304672.

The previous prime is 121761304631. The next prime is 121761304681. The reversal of 121761304673 is 376403167121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111107555584 + 10653749089 = 333328^2 + 103217^2 .

It is a cyclic number.

It is not a de Polignac number, because 121761304673 - 210 = 121761303649 is a prime.

It is a super-2 number, since 2×1217613046732 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 121761304673.

It is not a weakly prime, because it can be changed into another prime (121761304603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60880652336 + 60880652337.

It is an arithmetic number, because the mean of its divisors is an integer number (60880652337).

Almost surely, 2121761304673 is an apocalyptic number.

It is an amenable number.

121761304673 is a deficient number, since it is larger than the sum of its proper divisors (1).

121761304673 is an equidigital number, since it uses as much as digits as its factorization.

121761304673 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 127008, while the sum is 41.

The spelling of 121761304673 in words is "one hundred twenty-one billion, seven hundred sixty-one million, three hundred four thousand, six hundred seventy-three".