Base | Representation |
---|---|
bin | 1011000101001001101010… |
… | …0110111100101110110011 |
3 | 1121010200202122211111222102 |
4 | 2301102122212330232303 |
5 | 3044102013003343242 |
6 | 41524503143531015 |
7 | 2365126046100623 |
oct | 261223246745663 |
9 | 47120678744872 |
10 | 12183121152947 |
11 | 3977918306428 |
12 | 1449206759a6b |
13 | 6a4b2bb572a4 |
14 | 30194811a883 |
15 | 161d9e64ee32 |
hex | b149a9bcbb3 |
12183121152947 has 2 divisors, whose sum is σ = 12183121152948. Its totient is φ = 12183121152946.
The previous prime is 12183121152919. The next prime is 12183121152959. The reversal of 12183121152947 is 74925112138121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12183121152947 - 26 = 12183121152883 is a prime.
It is not a weakly prime, because it can be changed into another prime (12183121152047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6091560576473 + 6091560576474.
It is an arithmetic number, because the mean of its divisors is an integer number (6091560576474).
Almost surely, 212183121152947 is an apocalyptic number.
12183121152947 is a deficient number, since it is larger than the sum of its proper divisors (1).
12183121152947 is an equidigital number, since it uses as much as digits as its factorization.
12183121152947 is an evil number, because the sum of its binary digits is even.
The product of its digits is 241920, while the sum is 47.
The spelling of 12183121152947 in words is "twelve trillion, one hundred eighty-three billion, one hundred twenty-one million, one hundred fifty-two thousand, nine hundred forty-seven".
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