12183462375153 has 4 divisors (see below), whose sum is σ = 16244616500208. Its totient is φ = 8122308250100.

The previous prime is 12183462375151. The next prime is 12183462375209. The reversal of 12183462375153 is 35157326438121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12183462375153 - 2¹ = 12183462375151 is a prime.

It is a super-2 number, since 2×12183462375153² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12183462375096 and 12183462375105.

It is not an unprimeable number, because it can be changed into a prime (12183462375151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2030577062523 + ... + 2030577062528.

It is an arithmetic number, because the mean of its divisors is an integer number (4061154125052).

Almost surely, 2^{12183462375153} is an apocalyptic number.

It is an amenable number.

12183462375153 is a deficient number, since it is larger than the sum of its proper divisors (4061154125055).

12183462375153 is an equidigital number, since it uses as much as digits as its factorization.

12183462375153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4061154125054.

The product of its digits is 3628800, while the sum is 51.

The spelling of 12183462375153 in words is "twelve trillion, one hundred eighty-three billion, four hundred sixty-two million, three hundred seventy-five thousand, one hundred fifty-three".