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121890560153 is a prime number
BaseRepresentation
bin111000110000100111…
…1100101100010011001
3102122121202121000110212
41301201033211202121
53444112440411103
6131555025420505
711543363444405
oct1614117454231
9378552530425
10121890560153
114776a052a2a
121b758a9a735
13b656a9430b
145c84474105
153285e4b7d8
hex1c613e5899

121890560153 has 2 divisors, whose sum is σ = 121890560154. Its totient is φ = 121890560152.

The previous prime is 121890560149. The next prime is 121890560159. The reversal of 121890560153 is 351065098121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84968169049 + 36922391104 = 291493^2 + 192152^2 .

It is a cyclic number.

It is not a de Polignac number, because 121890560153 - 22 = 121890560149 is a prime.

It is a super-2 number, since 2×1218905601532 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 121890560153.

It is not a weakly prime, because it can be changed into another prime (121890560159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60945280076 + 60945280077.

It is an arithmetic number, because the mean of its divisors is an integer number (60945280077).

Almost surely, 2121890560153 is an apocalyptic number.

It is an amenable number.

121890560153 is a deficient number, since it is larger than the sum of its proper divisors (1).

121890560153 is an equidigital number, since it uses as much as digits as its factorization.

121890560153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 41.

The spelling of 121890560153 in words is "one hundred twenty-one billion, eight hundred ninety million, five hundred sixty thousand, one hundred fifty-three".