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12195108100793 is a prime number
BaseRepresentation
bin1011000101110110010100…
…0101100001101010111001
31121011211201001101120010202
42301131211011201222321
53044301040133211133
641534204425451545
72366032101343502
oct261354505415271
947154631346122
1012195108100793
113981a096627a2
12144b5b1040bb5
136a5cbc39bc37
143023640dbba9
15162351b932e8
hexb1765161ab9

12195108100793 has 2 divisors, whose sum is σ = 12195108100794. Its totient is φ = 12195108100792.

The previous prime is 12195108100741. The next prime is 12195108100811. The reversal of 12195108100793 is 39700180159121.

12195108100793 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7585683740944 + 4609424359849 = 2754212^2 + 2146957^2 .

It is a cyclic number.

It is not a de Polignac number, because 12195108100793 - 214 = 12195108084409 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12195108100723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6097554050396 + 6097554050397.

It is an arithmetic number, because the mean of its divisors is an integer number (6097554050397).

Almost surely, 212195108100793 is an apocalyptic number.

It is an amenable number.

12195108100793 is a deficient number, since it is larger than the sum of its proper divisors (1).

12195108100793 is an equidigital number, since it uses as much as digits as its factorization.

12195108100793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 47.

The spelling of 12195108100793 in words is "twelve trillion, one hundred ninety-five billion, one hundred eight million, one hundred thousand, seven hundred ninety-three".