Base | Representation |
---|---|
bin | 11011101110110110100101… |
… | …111100110000100101100011 |
3 | 120222211221001212202001111102 |
4 | 123232312211330300211203 |
5 | 111441301323420112203 |
6 | 1111222504104305015 |
7 | 34455552141301451 |
oct | 3356664574604543 |
9 | 528757055661442 |
10 | 121966970472803 |
11 | 359539a1183385 |
12 | 1181a02377216b |
13 | 5309588a769c1 |
14 | 2219338dc39d1 |
15 | e17992a81888 |
hex | 6eeda5f30963 |
121966970472803 has 2 divisors, whose sum is σ = 121966970472804. Its totient is φ = 121966970472802.
The previous prime is 121966970472797. The next prime is 121966970472829. The reversal of 121966970472803 is 308274079669121.
It is a weak prime.
It is an emirp because it is prime and its reverse (308274079669121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121966970472803 - 216 = 121966970407267 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 121966970472803.
It is not a weakly prime, because it can be changed into another prime (121966970472833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60983485236401 + 60983485236402.
It is an arithmetic number, because the mean of its divisors is an integer number (60983485236402).
Almost surely, 2121966970472803 is an apocalyptic number.
121966970472803 is a deficient number, since it is larger than the sum of its proper divisors (1).
121966970472803 is an equidigital number, since it uses as much as digits as its factorization.
121966970472803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54867456, while the sum is 65.
The spelling of 121966970472803 in words is "one hundred twenty-one trillion, nine hundred sixty-six billion, nine hundred seventy million, four hundred seventy-two thousand, eight hundred three".
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