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12200217026713 is a prime number
BaseRepresentation
bin1011000110001001010110…
…0110100010000010011001
31121012022220002201212222021
42301202111212202002121
53044342021024323323
641540411411454441
72366302515450322
oct261422546420231
947168802655867
1012200217026713
1139840a04a8421
121450597bb7421
136a6624978021
143026ca835449
1516255046405d
hexb18959a2099

12200217026713 has 2 divisors, whose sum is σ = 12200217026714. Its totient is φ = 12200217026712.

The previous prime is 12200217026689. The next prime is 12200217026731. The reversal of 12200217026713 is 31762071200221.

Together with next prime (12200217026731) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8982200809024 + 3218016217689 = 2997032^2 + 1793883^2 .

It is a cyclic number.

It is not a de Polignac number, because 12200217026713 - 217 = 12200216895641 is a prime.

It is not a weakly prime, because it can be changed into another prime (12200217026113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100108513356 + 6100108513357.

It is an arithmetic number, because the mean of its divisors is an integer number (6100108513357).

Almost surely, 212200217026713 is an apocalyptic number.

It is an amenable number.

12200217026713 is a deficient number, since it is larger than the sum of its proper divisors (1).

12200217026713 is an equidigital number, since it uses as much as digits as its factorization.

12200217026713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14112, while the sum is 34.

Adding to 12200217026713 its reverse (31762071200221), we get a palindrome (43962288226934).

The spelling of 12200217026713 in words is "twelve trillion, two hundred billion, two hundred seventeen million, twenty-six thousand, seven hundred thirteen".