Base | Representation |
---|---|
bin | 10001110000001111101… |
… | …001101110110101000011 |
3 | 11022122010012220200222121 |
4 | 101300033221232311003 |
5 | 124442112011410034 |
6 | 2332250415545111 |
7 | 154100364012466 |
oct | 21601751566503 |
9 | 4278105820877 |
10 | 1220033310019 |
11 | 43045aaa7457 |
12 | 17854a82b197 |
13 | 8b082b560c4 |
14 | 4309b0012dd |
15 | 21b088361b4 |
hex | 11c0fa6ed43 |
1220033310019 has 2 divisors, whose sum is σ = 1220033310020. Its totient is φ = 1220033310018.
The previous prime is 1220033309953. The next prime is 1220033310047. The reversal of 1220033310019 is 9100133300221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1220033310019 - 29 = 1220033309507 is a prime.
It is a super-2 number, since 2×12200333100192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1220033309975 and 1220033310002.
It is not a weakly prime, because it can be changed into another prime (1220033310319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610016655009 + 610016655010.
It is an arithmetic number, because the mean of its divisors is an integer number (610016655010).
Almost surely, 21220033310019 is an apocalyptic number.
1220033310019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220033310019 is an equidigital number, since it uses as much as digits as its factorization.
1220033310019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 1220033310019 in words is "one trillion, two hundred twenty billion, thirty-three million, three hundred ten thousand, nineteen".
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