Base | Representation |
---|---|
bin | 10001110000010011101… |
… | …000000010001010100001 |
3 | 11022122021212100120111021 |
4 | 101300103220002022201 |
5 | 124442231043130133 |
6 | 2332301200445441 |
7 | 154102133442511 |
oct | 21602350021241 |
9 | 4278255316437 |
10 | 1220099973793 |
11 | 430494699988 |
12 | 178569019881 |
13 | 8b0938c721c |
14 | 430a5bd5841 |
15 | 21b0e60352d |
hex | 11c13a022a1 |
1220099973793 has 2 divisors, whose sum is σ = 1220099973794. Its totient is φ = 1220099973792.
The previous prime is 1220099973761. The next prime is 1220099973797. The reversal of 1220099973793 is 3973799900221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1209313697344 + 10786276449 = 1099688^2 + 103857^2 .
It is a cyclic number.
It is not a de Polignac number, because 1220099973793 - 25 = 1220099973761 is a prime.
It is a super-4 number, since 4×12200999737934 (a number of 49 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (1220099973797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610049986896 + 610049986897.
It is an arithmetic number, because the mean of its divisors is an integer number (610049986897).
Almost surely, 21220099973793 is an apocalyptic number.
It is an amenable number.
1220099973793 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220099973793 is an equidigital number, since it uses as much as digits as its factorization.
1220099973793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11573604, while the sum is 61.
The spelling of 1220099973793 in words is "one trillion, two hundred twenty billion, ninety-nine million, nine hundred seventy-three thousand, seven hundred ninety-three".
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