Base | Representation |
---|---|
bin | 10001110000010100001… |
… | …111000011000011111001 |
3 | 11022122022120121011200201 |
4 | 101300110033003003321 |
5 | 124442241202413311 |
6 | 2332302204002201 |
7 | 154102316406622 |
oct | 21602417030371 |
9 | 4278276534621 |
10 | 1220110201081 |
11 | 43049a444892 |
12 | 178570530361 |
13 | 8b095a68385 |
14 | 430a72d8a49 |
15 | 21b104739c1 |
hex | 11c143c30f9 |
1220110201081 has 2 divisors, whose sum is σ = 1220110201082. Its totient is φ = 1220110201080.
The previous prime is 1220110200977. The next prime is 1220110201129. The reversal of 1220110201081 is 1801020110221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1214218871056 + 5891330025 = 1101916^2 + 76755^2 .
It is a cyclic number.
It is not a de Polignac number, because 1220110201081 - 239 = 670354387193 is a prime.
It is a super-2 number, since 2×12201102010812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1220110208081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610055100540 + 610055100541.
It is an arithmetic number, because the mean of its divisors is an integer number (610055100541).
Almost surely, 21220110201081 is an apocalyptic number.
It is an amenable number.
1220110201081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220110201081 is an equidigital number, since it uses as much as digits as its factorization.
1220110201081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
The spelling of 1220110201081 in words is "one trillion, two hundred twenty billion, one hundred ten million, two hundred one thousand, eighty-one".
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