Base | Representation |
---|---|
bin | 10001110000010100010… |
… | …010111001111000010011 |
3 | 11022122022122111112111001 |
4 | 101300110102321320103 |
5 | 124442241432241201 |
6 | 2332302241402431 |
7 | 154102331120224 |
oct | 21602422717023 |
9 | 4278278445431 |
10 | 1220111212051 |
11 | 43049aa753a6 |
12 | 178570939417 |
13 | 8b096030594 |
14 | 430a74bd24b |
15 | 21b105c3301 |
hex | 11c144b9e13 |
1220111212051 has 2 divisors, whose sum is σ = 1220111212052. Its totient is φ = 1220111212050.
The previous prime is 1220111211989. The next prime is 1220111212057. The reversal of 1220111212051 is 1502121110221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1220111212051 - 231 = 1217963728403 is a prime.
It is not a weakly prime, because it can be changed into another prime (1220111212057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610055606025 + 610055606026.
It is an arithmetic number, because the mean of its divisors is an integer number (610055606026).
Almost surely, 21220111212051 is an apocalyptic number.
1220111212051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220111212051 is an equidigital number, since it uses as much as digits as its factorization.
1220111212051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 1220111212051 its reverse (1502121110221), we get a palindrome (2722232322272).
The spelling of 1220111212051 in words is "one trillion, two hundred twenty billion, one hundred eleven million, two hundred twelve thousand, fifty-one".
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