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12201143313 = 34067047771
BaseRepresentation
bin10110101110011111…
…01010110000010001
31011111022121022002210
423113033222300101
5144441443041223
65334412502333
7611233002252
oct132717526021
934438538083
1012201143313
1151a1255617
12244617a9a9
1311c5a2c338
1483a61ab29
154b6253893
hex2d73eac11

12201143313 has 4 divisors (see below), whose sum is σ = 16268191088. Its totient is φ = 8134095540.

The previous prime is 12201143309. The next prime is 12201143327. The reversal of 12201143313 is 31334110221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12201143313 - 22 = 12201143309 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12201143313.

It is not an unprimeable number, because it can be changed into a prime (12201143393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2033523883 + ... + 2033523888.

It is an arithmetic number, because the mean of its divisors is an integer number (4067047772).

Almost surely, 212201143313 is an apocalyptic number.

It is an amenable number.

12201143313 is a deficient number, since it is larger than the sum of its proper divisors (4067047775).

12201143313 is an equidigital number, since it uses as much as digits as its factorization.

12201143313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4067047774.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 12201143313 its reverse (31334110221), we get a palindrome (43535253534).

The spelling of 12201143313 in words is "twelve billion, two hundred one million, one hundred forty-three thousand, three hundred thirteen".

Divisors: 1 3 4067047771 12201143313