Base | Representation |
---|---|
bin | 10001110000010100110… |
… | …101101100011101110011 |
3 | 11022122100021122212220101 |
4 | 101300110311230131303 |
5 | 124442301301112042 |
6 | 2332303205053231 |
7 | 154102501463353 |
oct | 21602465543563 |
9 | 4278307585811 |
10 | 1220120332147 |
11 | 4304a5134472 |
12 | 1785739b7217 |
13 | 8b097ba47a2 |
14 | 430a87b4b63 |
15 | 21b112c56b7 |
hex | 11c14d6c773 |
1220120332147 has 2 divisors, whose sum is σ = 1220120332148. Its totient is φ = 1220120332146.
The previous prime is 1220120332019. The next prime is 1220120332157. The reversal of 1220120332147 is 7412330210221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1220120332147 - 27 = 1220120332019 is a prime.
It is not a weakly prime, because it can be changed into another prime (1220120332157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610060166073 + 610060166074.
It is an arithmetic number, because the mean of its divisors is an integer number (610060166074).
Almost surely, 21220120332147 is an apocalyptic number.
1220120332147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220120332147 is an equidigital number, since it uses as much as digits as its factorization.
1220120332147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 1220120332147 its reverse (7412330210221), we get a palindrome (8632450542368).
The spelling of 1220120332147 in words is "one trillion, two hundred twenty billion, one hundred twenty million, three hundred thirty-two thousand, one hundred forty-seven".
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