Base | Representation |
---|---|
bin | 1011000110001101000110… |
… | …0000100111111011001011 |
3 | 1121012102111010222110022101 |
4 | 2301203101200213323023 |
5 | 3044401100330022143 |
6 | 41541055234134231 |
7 | 2366336441515066 |
oct | 261432140477313 |
9 | 47172433873271 |
10 | 12201222110923 |
11 | 398456688402a |
12 | 1450818721377 |
13 | 6a6754c75401 |
14 | 3027841078dd |
15 | 1625ad7ebb4d |
hex | b18d1827ecb |
12201222110923 has 2 divisors, whose sum is σ = 12201222110924. Its totient is φ = 12201222110922.
The previous prime is 12201222110897. The next prime is 12201222110933. The reversal of 12201222110923 is 32901122210221.
12201222110923 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12201222110923 - 217 = 12201221979851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12201222110891 and 12201222110900.
It is not a weakly prime, because it can be changed into another prime (12201222110933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100611055461 + 6100611055462.
It is an arithmetic number, because the mean of its divisors is an integer number (6100611055462).
Almost surely, 212201222110923 is an apocalyptic number.
12201222110923 is a deficient number, since it is larger than the sum of its proper divisors (1).
12201222110923 is an equidigital number, since it uses as much as digits as its factorization.
12201222110923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 28.
The spelling of 12201222110923 in words is "twelve trillion, two hundred one billion, two hundred twenty-two million, one hundred ten thousand, nine hundred twenty-three".
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