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1220130141401 = 2731274467263
BaseRepresentation
bin10001110000010101011…
…011000111010011011001
311022122100222010020200002
4101300111123013103121
5124442311304011101
62332304155222345
7154102651036643
oct21602533072331
94278328106602
101220130141401
114304aa724296
121785771479b5
138b099c2a592
14430a9c09893
1521b120b1d6b
hex11c156c74d9

1220130141401 has 4 divisors (see below), whose sum is σ = 1220134881792. Its totient is φ = 1220125401012.

The previous prime is 1220130141281. The next prime is 1220130141407. The reversal of 1220130141401 is 1041410310221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1220130141401 - 230 = 1219056399577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1220130141407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1960505 + ... + 2506758.

It is an arithmetic number, because the mean of its divisors is an integer number (305033720448).

Almost surely, 21220130141401 is an apocalyptic number.

It is an amenable number.

1220130141401 is a deficient number, since it is larger than the sum of its proper divisors (4740391).

1220130141401 is an equidigital number, since it uses as much as digits as its factorization.

1220130141401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4740390.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 1220130141401 its reverse (1041410310221), we get a palindrome (2261540451622).

The spelling of 1220130141401 in words is "one trillion, two hundred twenty billion, one hundred thirty million, one hundred forty-one thousand, four hundred one".

Divisors: 1 273127 4467263 1220130141401