122014513473 has 4 divisors (see below), whose sum is σ = 162686017968. Its totient is φ = 81343008980.

The previous prime is 122014513441. The next prime is 122014513477. The reversal of 122014513473 is 374315410221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 374315410221 = 3 ⋅124771803407.

It is a cyclic number.

It is not a de Polignac number, because 122014513473 - 2⁵ = 122014513441 is a prime.

It is not an unprimeable number, because it can be changed into a prime (122014513477) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20335752243 + ... + 20335752248.

It is an arithmetic number, because the mean of its divisors is an integer number (40671504492).

Almost surely, 2^122014513473 is an apocalyptic number.

It is an amenable number.

122014513473 is a deficient number, since it is larger than the sum of its proper divisors (40671504495).

122014513473 is an equidigital number, since it uses as much as digits as its factorization.

122014513473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40671504494.

The product of its (nonzero) digits is 20160, while the sum is 33.

Adding to 122014513473 its reverse (374315410221), we get a palindrome (496329923694).

The spelling of 122014513473 in words is "one hundred twenty-two billion, fourteen million, five hundred thirteen thousand, four hundred seventy-three".