Base | Representation |
---|---|
bin | 10001110000011010111… |
… | …001100110111000001011 |
3 | 11022122121101000012222001 |
4 | 101300122321212320023 |
5 | 124443003314134011 |
6 | 2332321240411431 |
7 | 154105145021611 |
oct | 21603271467013 |
9 | 4278541005861 |
10 | 1220222021131 |
11 | 430547579953 |
12 | 1785a1a76b77 |
13 | 8b0b2c89c99 |
14 | 430b80c56b1 |
15 | 21b1a1b07c1 |
hex | 11c1ae66e0b |
1220222021131 has 2 divisors, whose sum is σ = 1220222021132. Its totient is φ = 1220222021130.
The previous prime is 1220222021077. The next prime is 1220222021147. The reversal of 1220222021131 is 1311202220221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1220222021131 - 27 = 1220222021003 is a prime.
It is a super-2 number, since 2×12202220211312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1220222021099 and 1220222021108.
It is not a weakly prime, because it can be changed into another prime (1220222028131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610111010565 + 610111010566.
It is an arithmetic number, because the mean of its divisors is an integer number (610111010566).
Almost surely, 21220222021131 is an apocalyptic number.
1220222021131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220222021131 is an equidigital number, since it uses as much as digits as its factorization.
1220222021131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 1220222021131 its reverse (1311202220221), we get a palindrome (2531424241352).
The spelling of 1220222021131 in words is "one trillion, two hundred twenty billion, two hundred twenty-two million, twenty-one thousand, one hundred thirty-one".
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